Command to find patch folders that can be deleted from .patch_storage

According to this Doc, I can remove the patch folder in .patch_storage if the patch is not listed in opatch inventory.

How To Avoid Disk Full Issues Because OPatch Backups Take Big Amount Of Disk Space. (Doc ID 550522.1)

The following two scripts work the same way, they list the patch number that has zero match in opatch inventory.

#1:

$ORACLE_HOME/OPatch/opatch lsinventory>dropit; for patch in `ls|cut -d "_" -f 1|grep [0-9]`;  do echo $patch:`grep -c $patch dropit`; done|awk -F":" '{if ($2==0) print $0}'

#2

ls $ORACLE_HOME/.patch_storage|cut -d "_" -f 1|grep [0-9] > patchstorage.txt; $ORACLE_HOME/OPatch/opatch lsinventory>opatchinventory.txt; for patch in `cat patchstorage.txt`; do echo $patch:`grep -c $patch opatchinventory.txt`; done|awk -F":" '{if ($2==0) print $0}'

sample output:

19872484:0

20299018:0

20831113:0

21436941:0

23854735:0

#3: this will display the ls command of those patch number that can be deleted:

run as $oracle_home owner, do not run as root, otherwise "opatch lsinventory" will fail and ends up listing all folders can be deleted.

ls -lrt $ORACLE_HOME/.patch_storage > patchstoragelist.txt; ls -rt $ORACLE_HOME/.patch_storage|cut -d "_" -f 1|grep [0-9] > patchstoragenumber.txt; $ORACLE_HOME/OPatch/opatch lsinventory>opatchinventory.txt; for patch in `cat patchstoragenumber.txt`; do echo $patch:`grep -c $patch opatchinventory.txt`; done|awk -F":" '{if ($2==0) print $0}'|cut -d ":" -f 1 > candeletepatch.txt; for patch in `cat candeletepatch.txt` ; do grep $patch patchstoragelist.txt; done

sample output:

drwxr-xr-x  4 grid oinstall  4096 Jul 20  2015 20299018_Mar_4_2015_23_52_42
drwxr-xr-x  4 grid oinstall  4096 Jul 20  2015 20831113_Jun_22_2015_07_20_06
drwxr-xr-x  4 grid oinstall  4096 Nov 10  2016 23854735_Sep_29_2016_23_50_00

drwxr-xr-x  4 grid oinstall  4096 Nov 10  2016 24007012_Aug_30_2016_00_17_17

Now you can remove the folders:

rm -rf thefoldername